Cara penyelesaian dari 8/3 + 7/4 + 7/8 - 1/8

[tex] \frac{8}{3} + \frac{7}{4} + \frac{7}{8} - \frac{1}{8} \\ = \frac{64 + 42 + 21 - 3}{24} \\ = \frac{124}{24} \\ = \frac{31}{6} [/tex]
Semoga terbantu