Matematika

Pertanyaan

tolong di bantuu plissss kakk
tolong di bantuu plissss kakk

2 Jawaban

  • Penyelesaian :

    Panjang AC
    [tex] = \sqrt[2]{ {8}^{2} + {6}^{2} } \\ = \sqrt[2]{64 + 36} \\ = \sqrt[2]{100} = 10 \: \: cm[/tex]

    Panjang AD
    [tex] = \sqrt[2]{ {10}^{2} + {24}^{2} } \\ = \sqrt[2]{100 + 576} \\ = \sqrt[2]{676} = 26 \: \: cm[/tex]
    Opsi => C

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  • Jawab :
    panjang Ac
    [tex] = \sqrt[2]{ {8}^{2} + {6}^{2} } \\ = \sqrt[2]{64 + 36} \\ = \sqrt[2]{100} \\ = 10 \: cm[/tex]
    Panjang AD
    [tex] = \sqrt[2]{ {10}^{2} + {24}^{2} } \\ = \sqrt[2]{100 + 576} \\ = \sqrt[2]{676} \\ = 26 \: \: cm[/tex]
    jawabanya C

    semoga membantu :)