Tolong jawab no 7 A dan B

Luas persegi panjang = pl
P= 30
L= 2y+1
Luas maksimal 150 m²

A. Lebar maksimal
L = p.l <= 150
<=> 30 × 2y + 1 <= 150
<=> 60y + 30 <= 150
<=> 2y + 1 <= 5
<=> 2y <= 5 - 1
<=> 2y <= 4
<=> y <= 2
Lebar maksimal = 2(2) + 1 = 5m

B.
Harga per m² = Rp4.500.000,-
Luas maksimal = 150m²

Harga total maksimal = Rp4.500.000,- × 150m² = Rp665.000.000,-