soal logaritma dan pembahasan

[tex]jika \: {}^{27} log(25) = p. \: maka \: {}^{5 } log(81) = ... \\ penyelesaian \\ {}^{27} log(25) = p \\ {}^{ {3}^{3} } log( {5}^{2} ) = p \\ \frac{2}{3} {}^{3} log(5) = p \\ {}^{3} log(5) = \frac{3p}{2} = > {}^{5} log(3) = \frac{2}{3p} \\ {}^{5} log(81) = {}^{5} log( {3}^{4} ) \\ = 4. {}^{5 } log(3) \\ = 4( \frac{2}{3p} ) \\ = \frac{8}{3p} [/tex]