koordinat titik balik dari fungsi kuadrat f(x)=4x²-5x+1

a = 4 , b= -5 , c= 1

titik balik (-b/2a , -D/4a)

x = -b/2a
= -(-5)/2(4)
= 5/8

D = b² - 4ac
= (-5)² - 4(4)(1)
= 25 - 16
= 9

y = -D/4a
= -9/4(4)
= -9/16

titik balik (5/8 , -9/16)

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