loɡ (√(4+√15) + loɡ √(4−√15) ) =
Matematika
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Pertanyaan
loɡ (√(4+√15) + loɡ √(4−√15) ) =
1 Jawaban
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1. Jawaban dedenkusnandar
Loɡ (4+√15)^½ + loɡ (4−√15)^ ½ =
½ log (4 + √15) + ½ log (4 - √15) =
½ log ( (4 + √15) × (4 - √15) ) =
½ log (16 - 15) =
½ log 1 =
log 1^½ =
log √1 =
log 1