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1 Jawaban

  • 4 NH3 + 5 O2 -> 4 NO + 6 H2O

    Mr O2 = 2 × 16 = 32
    n O2 = m / Mr = 24 / 32 = 0,75 mol

    n NO = (koefisien NO / koefisien O2) × n O2
    = (4 / 5) × 0,75 mol
    = 0,6 mol

    V NO = n × V stp
    = 0,6 mol × 22,4 L/mol
    = 13,44 L.

    D. 13,44 L