Nilai dari integral 2 atas dan -1 bawah (2x pangkat 2+1) (2x-3)dx

[tex] \int_{ - 1}^2(2 {x}^{2} + 1)(2x - 3)dx \\ = \int_{ - 1}^2(2 {x}^{3} - 6 {x}^{2} + 2x - 6)dx \\ = \frac{1}{2} {x}^{4} - 2 {x}^{3} + {x}^{2} - 6x \: |_{ - 1}^2 \\ = (\frac{1}{2} {(2)}^{4} - 2 {(2)}^{3} + {(2)}^{2} - 6(2)) - (\frac{1}{2} {( - 1)}^{4} - 2 {( - 1)}^{3} + {( - 1)}^{2} - 6( - 1)) \\ = (8 - 16 + 4 - 12) - ( \frac{1}{2} + 2 + 1 + 6) \\ = - 16 - \frac{1}{2} - 9 \\ = - 25 \frac{1}{2} [/tex]