Dik: notasi fungsi fx -> 2x*kuadrat 2* - × + 1 dengan domain {-2,-1,0,1,2} Tentukan : a. Rumus Fungsi b. Range d. Himpunan pasangan berurutan Bantuin yaahhhh ,,

[tex]a) \hspace{1 mm} Rumus \hspace{1 mm} fungsi: f(x) = 2x^2 - x + 1 \\ b) \hspace{1 mm} Range: \\ f(-2) = 2(-2)^2 - (-2) + 1 = 11 \\ f(-1) = 2(-1)^2 -(-1) + 1 = 4 \\ f(0) = 2(0)^2 -(0) + 1 = 1 \\ f(1) = 2(1)^2 -(1) + 1 = 2 \\ f(2) = 2(2)^2 -(2) + 1 = 7 \\ rangenya: {1,2,4,7,11} \\ c) \hspace{1 mm} (-2,11),(-1,4),(0,1),(1,2),(2,7)[/tex]

a. Rumus fungsi = f(x) = 2x² -x +1
b. f(-2) = 2(-2)² -(-2) +1
           = 8 +2 +1
           = 11
   f(-1) = 2(-1)² -(-1) +1
           = 2 +1 +1
           = 4
  f(0) = 2(0)² -0 +1
         = 1
  f(1) = 2(1)² -1 +1
       = 2 -1 +1
       = 2
  f(2) = 2(2)² -2 +1
         = 8 -2 +1
         = 7
Range = {1, 2, 4, 7,11}
c. {(-2,11),(-1,4),(0,1),(1,2),(2,7)}