jika 70 mL CH3COOH 0,1 M direaksikan dengan 100 mL NaOH 0,05 M, pH larutan akhir adalah

• CH3COOH --> Asam Lemah
• NaOH --> Basa Kuat
° Asam dengan basa akan bereaksi
• nCH3COOH = V.M = 0,07 L.0,1 M = 0,007 mol
• nNaOH = V.M = 0,1 L.0,05 M = 0,005 mol
* CH3COOH + NaOH -> CH3COONa + H20
M: 0,007 0,005 -
R: 0,005 0,005 0,005
S: 0,002 - 0,005
•[H+] = Ka. na/x.ng
= 10^-5. 0,002/1.0,005
= 10^-5. 4. 10^-1
= 4.10^-6 M
• pH = - log [H+]
= - log 4.10^-6
= 6 - log 4
= 6 - 0,602
= 5,398
= 5,4