Matematika

Pertanyaan

diketahui vektor a=(3,-1) dan b=(2,3) . tentukan ; a). vektor c=a-b b). panjang vektor a,b,dan c

1 Jawaban

  • c = [(3-2),(-1-3)]
    c = (1,-4)
    panjang vektor
    [tex] |a| = \sqrt{3^{2} + { - 1}^{2} } \\ = \sqrt{9 + 1} \\ = \sqrt{10} [/tex]
    [tex] |b| = \sqrt{ {2}^{2} + {3}^{2} } \\ = \sqrt{4 + 9} \\ = \sqrt{13} [/tex]
    [tex] |c| = \sqrt{ {1}^{2} + { - 4}^{2} } \\ = \sqrt{1 + 16} \\ = \sqrt{17} [/tex]

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