hasil sederhana dari 3√24 : √18 x √6

Operasi Bentuk Akar

[tex]3 \sqrt{24} \div \sqrt{18} \times \sqrt{6} \\ = 3 \sqrt{24} \div \sqrt{9 \times 2} \times \sqrt{6} \\ = 3 \sqrt{24} \div 3 \sqrt{2} \times \sqrt{6} \\ = 3 \div 3 \times \sqrt{24 \div 2 \times 6} \\ = \sqrt{72} \\ = \sqrt{36 \times 2} \\ = 6 \sqrt{2} [/tex]

*semoga membantu. sukses selalu ^_^