tolong bantuannya 2 lagi aja

int= integral
[tex]i) \\ int \: \frac{ {(2x - 5)}^{2} }{ \sqrt{x} } dx = int \: (4 {x}^{2} - 20x + 25)( {x}^{ - \frac{1}{2} } ) \: dx \\ = int \: (4 {x}^{ \frac{3}{2} } - 20 {x}^{ \frac{1}{2} } + 25 {x}^{ - \frac{1}{2} } ) \: dx \\ = \frac{4}{ \frac{3}{2} + 1} {x}^{ \frac{3}{2} + 1 } - \frac{20}{ \frac{1}{2} + 1} {x}^{ \frac{1}{2} + 1 } + \frac{25}{ - \frac{1}{2} + 1 } {x}^{ - \frac{1}{2} + 1} + c\\ = \frac{4}{ \frac{5}{2} } {x}^{ \frac{5}{2} } - \frac{20}{ \frac{3}{2} } {x}^{ \frac{3}{2} } + \frac{25}{ \frac{1}{2} } {x}^{ \frac{1}{2} } + c \\ = \frac{8}{5} {x}^{ \frac{5}{2} } - \frac{40}{3} {x}^{ \frac{3}{2} } + 50 {x}^{ \frac{1}{2} } + c[/tex]
yang i cek diatas...
kalo yang j, cek bawah...
[tex]int \: (9 - 6x + {x}^{2} )( {x}^{ - \frac{2}{3} } )dx \\ = int \: (9 {x}^{ - \frac{2}{3} } - 6 {x}^{ \frac{1}{3} } + {x}^{ \frac{4}{3} } ) \: dx \\ = \frac{9}{ - \frac{2}{3} + 1} {x}^{ - \frac{2}{3} + 1} - \frac{6}{ \frac{1}{3} + 1 } {x}^{ \frac{1}{3} + 1 } + \frac{1}{ \frac{4}{3} + 1} {x}^{ \frac{4}{3} + 1} + c \\ =27 {x}^{ \frac{1}{3} } - \frac{18}{4} {x}^{ \frac{4}{3} } + \frac{3}{7} {x}^{ \frac{7}{3} } + c[/tex]