Matematika

Pertanyaan

tentukan jumlah setiap deret geometri berikut a. 2+6+28+54+162+...+U7
b.3+15+75+...+U6
c.1+4+16+64+...+U7
d.5+10+20+40+80+...+U8
e.¼+½+1+2+...+U10

1 Jawaban

  • a.) a = 2
    r = 3
    Sn = a ( r^n - 1 ) / ( r - 1 )
    S7 = 2 ( 3^7 - 1 ) / ( 3 - 1 )
    = 2 ( 2187 - 1 ) / 2
    S7 = 2186

    b.) a = 3
    b = 5
    S6 = 3 ( 5^6 - 1 ) / ( 5 - 1 )
    = 3( 15625 - 1 ) / 4
    = 3( 3906 )
    = 11.718

    c.) a = 1
    b = 4
    S7 = 1 ( 4^7 - 1 ) / ( 4 - 1 )
    = ( 16384 - 1 ) / 3
    = 5461

    d.) a = 5
    b = 2
    S8 = 5 ( 2^8 - 1 ) / ( 2 - 1 )
    = 5 ( 256 - 1 ) / 1
    = 5 ( 255 )
    = 1275

    e.) a = 1/4
    b = 2
    S10 = 1/4 ( 2^10 - 1 ) / ( 2 - 1 )
    = 1/4 ( 1024 - 1 ) / 1
    = 1/4 ( 1023 )
    = 255 3/4

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