(xy³)¹/ (x-¹y²) ³= a. x²y-⁹ b. x-⁴y³ c. x⁴y-³ d. x²y³

[tex] \frac{(x {y}^{3} ) ^{1} }{( {x}^{ - 1} {y}^{2} ) ^{3} } = \frac{x {y}^{3} }{ {x}^{ - 3} {y}^{6} } \\ = {x}^{1 - ( - 3)} {y}^{3 - 6} \\ = {x}^{4} {y}^{ - 3} [/tex]
jawaban C