Diketahui barisan aritmatika dengan U3=7 dan U11=47, maka U101 adalah.....

U3 = a+2b = 7 U11 = a+10b = 47 dieleminasi b = 5 a = -3 U101 = a+100b = -3 + 100.(5) = 497

a + 10b = 47
a + 2b = 7
__________ -
8b = 40
b = 5
a = - 3
U101 = a + 100b
        = - 3 + 100(5)
        = 497