Matematika

Pertanyaan

hitunglah 3log 36 + 9log 3(1 per 16)

1 Jawaban

  • 3log 36 + 9log 3(1/16)
    =3log (3^2) x (2^2) + 3^2log 3 x 2^-4
    =3log3 + 3log3 + 3log2 + 3log2 + (-4/2) 3log3 + 3log2
    =1+1+3log2+3log2+ (-2)1+3log2
    =2-2+3log2+3log2+3log2
    =3log(2x2x2)
    =3log8
    =2

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