Matematika

Pertanyaan

persamaan garis singgung elips 3x^ + 4y^ - 6x + 8y - 45 = 0
di titik (-3, -2) adalah...
a. 3x + y + 11 = 0
b. 3x -y + 7 + 0
c. 3x - 2y + 5 = 0
d. x + 3y + 9 = 0
e. x - 3y - 3 = 0


tolong segera dibantu yaa...

2 Jawaban

  • [tex]3x^2+4y^2-6x+8y-45=0 \\ 3x^2-6x+4y^2+8y-45=0 \\ 3(x^2-2x+1)+4(y^2+2y+1)-45=3+4 \\ 3(x-1)^2+4(y+1)^2=52 \\ $Garis singgung$ \\ 3(x-1)(x_1-1)+4(y+1)(y_1+1)=52 \\ 3(x-1)(-3-1)+4(y+1)(-2+1)=52 \\ -12(x-1)-4(y+1)=52 \\ 3(x-1)+y+1=-13 \\ 3x-3+y+1=-13 \\ 3x+y+11=0[/tex]
  • 3x²+4x²-6x+8y-45=0 , (-3,-2)
    menggunakn cara cepat:
    3x1x +4y1y -3(x1+x) +4(y1+y) -45 = 0
    3(-3)x +4(-2)y - 3(-3+x) +4(-2+y)-45 =0
    -9x -8y+9 - 3x -8+4y-45 =0
    -9x-3x -8y +4y +9-8-45 = 0
    -12x-4y -44 = 0  :4
    -3x - y -11 =0
    =3x +y +11 = 0 (a)

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