tolong bantu jawab karna buat bsk tugas nya itu jawab nya per nomor di balok nya beserta caranya

Rumus tekanan zat padat
[tex]p = \frac{f}{a} [/tex]

Balok 1
[tex]p = \frac{160n}{4 \times 4} [/tex]
[tex]p = \frac{160n}{4 \times 4} [/tex]
[tex]p = \frac{160 \: n}{16 \: cm2} [/tex]
[tex]p = \frac{160n}{0.0016 \: m2} [/tex]
P = 100.000 N/m²


Balok 2
[tex]p = \frac{160n}{5 \times 4} [/tex]
[tex]p = \frac{160 \:n}{20 \: cm2} [/tex]
[tex]p = \frac{160 \: n}{0.002 \: m2} [/tex]
P = 8.000 N/m²


Balok 3
[tex]p = \frac{160 \: n}{2 \times 2} [/tex]
[tex]p = \frac{160 \: n}{4 \: cm2} [/tex]
[tex]p = \frac{160 \: n}{0.0004 \: m2} [/tex]
P = 400.000 N/m²


Balok 4
[tex]p = \frac{160 \: n}{3 \times 4} [/tex]
[tex]p = \frac{16 \: n}{12 \: cm2} [/tex]
[tex]p = \frac{160 \: n}{0.0012 \: m2} [/tex]
P = 133.333,3 N /m²

Semoga membantu:)