tolong nomor 1 dan 2 yaa
Matematika
diana3533
Pertanyaan
tolong nomor 1 dan 2 yaa
2 Jawaban
-
1. Jawaban code14
menggunakan perbandingan senilai
1. a)
AB/9 = (4+6)/6
AB/9 = 10/6
AB = 10/6 × 9
AB = 90/6
AB = 15 cm
AP = AB - BP
AP = 15 - 9
AP = 6 cm
1.b)
AC/15 = 15/9
AC = 15/9 × 15
AC = 225/9
AC = 25 cm
2.
EF/20 = 9/(9+3)
EF/20 = 9/12
EF = 9/12 × 20
EF = 180/12
EF = 15 cm -
2. Jawaban nspmunawip3gr44
1.
PQ :AC = BQ : BC
15 : AC = 6 : 10
6AC = 150
AC = 150/6 = 25 cm
PQ : AC = BP : AB
15 : 25 = 9 : (BP + AP)
15 : 25 = 9 : (9 + AP)
15(9 +AP) = 9 (25)
135 + 15AP = 225
15AP = 225 - 135
15AP = 90
AP = 90/15 = 6 cm
2.
AB : BC = EF : CF
20 : 12 = EF : 9
12EF = 20x9
12EF = 180
EF = 180/12 = 15 cm