Titik puncak dari persamaan kuadrat y=1/2x²+x-2/3

jawab

fungsi kuadrat
y = 1/2 x² + x - 2/3

y' = 0
1/2 x + 1 = 0
1/2 x = -1
x = - 2

y= 1/2 x² + x - 2/3
x = - 2 --> y =  1/2 (-2)² + (-2) - 2/3
y = 1/2 (4)  - 2 - 2/3
y = - 2/3

tik puncak (x,y)= (-2, - 2/3)