Jika F1=50N, diameter penghisap tekan setengah kali diameter pengisap beban, maka agar kedua pengisap seimbang, F2 harus...

[tex] F_{2}= ( \frac{D_{2}^{2}}{D_{1}^{2}}).F_{1} \\ F_{2}= ( \frac{x^{2}}{2x^{2}}).50 \\ F_{2}= \frac{1}{2} .50 \\ F_{2}= 25N [/tex]